1 / 71

Chapter 7

Chapter 7. Linear Programming. Instructor: Nguyen Ngoc Trung nguyenngoctrung.dhsp@gmail.com. Contents. Graphing Linear Inequalities in two variables Linear Programming: The graphical Method Applications of Linear Programming The Simplex Method: Maximization Maximization applications

donald
Télécharger la présentation

Chapter 7

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 7 Linear Programming Instructor: Nguyen Ngoc Trung nguyenngoctrung.dhsp@gmail.com

  2. Contents • Graphing Linear Inequalities in two variables • Linear Programming: The graphical Method • Applications of Linear Programming • The Simplex Method: Maximization • Maximization applications • The Simplex Method: Duality and Minimization • The Simplex Method: Nonstandard Problems Finite Maths

  3. Section 7.1 Graphing Linear Inequalities in two Variables Instructor: Nguyen Ngoc Trung nguyenngoctrung.dhsp@gmail.com

  4. Linear inequalities • Example: • A solution of a linear inequality is an ordered pair that satisfies the inequality. • Example: (1,1) is a solution of the inequality x+2y<4 • An linear inequality has an infinite number of solution • Solutions of a inequality is showed by the graph of it. Finite Maths

  5. Linear Inequalities (cont) • Example: Graph the inequality: 3x-2y ≤ 6 We have: Solution region Finite Maths

  6. The line is not in solution area!!! Linear Inequalities (cont) • Example: Graph the inequality: x+4y<4 We have: Solution region Finite Maths

  7. Linear inequalities (cont) • Example: Graph the inequality: 4y-2x > 6 Graphing: • The boundary line: 4y - 2x = 6 • X-intercept: y = 0  x = -3 • Y-intercept: x = 0  y = 1.5 Identify solution area: • The solution is either aboveor below the boundary line • Consider the point (0,0) • Let x=0 and y=0: • Therefore (0,0) is not in the solution area. • The solution area is above the boundary line. Solution Region Finite Maths

  8. Linear Inequalities (cont) • Example: Graph following inequalities and identify the solution region. Finite Maths

  9. System of Inequalities • System of inequalities: a set of at least 2 inequalities • Example: • Solve each inequalities for y: Feasible Region Finite Maths

  10. System of inequalities (cont) • Example: Feasible Region Finite Maths

  11. System of inequalities (cont) • Example: Feasible Region Finite Maths

  12. Application • See example 8. (p.373, textbook) • System of inequalities Feasible Region Finite Maths

  13. Section 7.2 Linear Programming:The Graphical Method Instructor: Nguyen Ngoc Trung nguyenngoctrung.dhsp@gmail.com

  14. Example • Consider again example 8: z • Price: • 2$ per unit of plates • 3$ per a unit of cups • Profit function: • z = 2x + 3y • Maximum profit = maximum of z Finite Maths

  15. Linear Programming • Constraints: linear inequalities that must be satisfied. • Objective function: linear function to be optimized • Example: Find the maximum and minimum values of the objective function: z = 2x+5y Finite Maths

  16. Linear Programming (cont) • Constraints: z z = 20 • Objective function: z = 2x + 5y • zmin=??? • zmax=??? zmax = ? z = 10 zmin = ? z = 5 z = 0 Finite Maths

  17. Corner points A B C E D Finite Maths

  18. Corner point theorem • If the feasible region is bounded, the objective function has both a maximum and a minimum value and each occurs at one or more corner points. • If the feasible region is unbounded, the objective function may not have a maximum or minimum. But if a maximum or minimum value exists, it will occurs at one or more corner points. • Maximum value occurs at a corner point • Minimum value occurs at a corner point • Maximum value occurs at 2 corner points • Minimum value occurs at a corner point • No maximum value • Minimum value occurs at a corner point Finite Maths

  19. Solving a linear programming problem • Write the objective function and all necessary contraints • Graph the feasible region • Determine the coordinates of each of the corner points • Find the value of the objective function at each corner point • Using corner point theorem to find maximum and minimum values Finite Maths

  20. Example Objective function: z = 5x+2y Finite Maths

  21. Section 7.3 Application of linear programming Instructor: Nguyen Ngoc Trung nguyenngoctrung.dhsp@gmail.com

  22. Example 1. • See example 1. (page 384, textbook) • Objective function: z = 7x + 20y • Constraints: Finite Maths

  23. Example 1 (cont) Finite Maths

  24. Example 2. • See example 2. (page 385, textbook) • Objective function: z = 8x + 12y • Constraints: Finite Maths

  25. Example 2 (cont) Finite Maths

  26. Example 3. • See example 3. (page 387, textbook) • Objective function: z = 0.18x + 0.12y • Constraints: Finite Maths

  27. Example 3 (cont) Finite Maths

  28. Section 7.4 The Simplex Method:Maximization Instructor: Nguyen Ngoc Trung nguyenngoctrung.dhsp@gmail.com

  29. Introduction • The method was developed by G.B.Danzig in 1947 • Variables: x1 , x2 , … instead of x, y, z • Constraints: a1x1 + a2x2 + … + anxn ≤ b Finite Maths

  30. Standard Maximum Form • The objective function is to be maximized • All variables are nonnegative (xi ≥ 0, i = 1, 2, 3 …) • All constraints involve ≤ • The constants on the right side in the constraints are all nonnegative (b ≥ 0) Finite Maths

  31. Slack variables Standard Maximum Form (cont) • Example: Finite Maths

  32. x1 x2 x3 x4 x5 x6 z Constraint 1 Constraint 2 Constraint 3 Objective Function Indicators Standard Maximum Form (cont) Finite Maths

  33. Smallest Most negative indicator x1 x1 x2 x2 x3 x3 x4 x4 x5 x5 x6 x6 z z Selecting the Pivot Quotients Finite Maths

  34. x1 x1 x2 x2 x3 x3 x4 x4 x5 x5 x6 x6 z z Pivoting R1 = R1 – R2 R3 = R3 – 2*R2 R4 = R4 + 3*R2 Finite Maths

  35. Pivotrow Smallest x1 x1 x2 x2 x3 x3 x4 x4 x5 x5 x6 x6 z z Most negative indicator: Pivot column Selecting the new Pivot Quotients Finite Maths

  36. x1 x1 x2 x2 x3 x3 x4 x4 x5 x5 x6 x6 z z No negative indicator: Stop!!!!! Pivoting again R2 = R2 – 0.5*R1 R3 = R3 – 2*R1 R4 = R4 + 0.5*R2 The final simplex tableau Finite Maths

  37. Non-basic variables Basic variables Maximize value of z x1 x2 x3 x4 x5 x6 z Reading solution Solution: The maximum value of z is 250,where x1=50, x2=50 and x3=0 Finite Maths

  38. Simplex Method • Determine the objective function • Write all necessary constraints • Convert each constraint into an equation by adding slack variables • Set up the initial simplex tableau • Locate the most negative indicator. If there are two such indicators, choose one. This indicator determines the pivot column • Use the positive entries in the pivot column to form the quotients necessary for determining the pivot. If there are no positive entries in the pivot column, no maximum solution exists. If two quotients are equally the smallest, let either determine the pivot Finite Maths

  39. Simplex Method (cont) • Multiply every entry in the pivot row by the reciprocal of the pivot to change the pivot to 1. Then use row operations to change all other entries in the pivot column to 0 by adding suitable multiples of the pivot row to the other rows • If the indicators are all positive or 0, you have found the final tableau. If not, go back to step 5 and repeat the process until a tableau with no negative indicators is obtained. • In the final tableau, the basic variables correspond to the columns that have one entry 1 and the rest 0. The non-basic variables correspond to the other columns. Set each non-basic variable equal to 0 and solve the system for the basic variables. The maximum value of the objective function is the number in the low right-hand corner of the final tableau. Finite Maths

  40. Section 7.5 Maximization Applications Instructor: Nguyen Ngoc Trung nguyenngoctrung.dhsp@gmail.com

  41. See example 1, 2, 3 (page 405 – 408, textbook) Finite Maths

  42. Section 7.6 Simplex Method:Duality and Minimization Instructor: Nguyen Ngoc Trung nguyenngoctrung.dhsp@gmail.com

  43. Transpose of a matrix • A transpose of matrix A is the matrix obtained by interchanging the rows and columns of A Finite Maths

  44. Minimization • The objective function is to be minimized • All coefficients of the objective function are nonnegative • All constraints involve ≥ • All variables are nonnegative • Note: • We y1, y2,… as variable and denote the objective function by w Finite Maths

  45. Minimization (cont) • Any solution of a maximizing problem produces the solution of an associated minimizing problem. • The associated problem is called the dual of the other. • Duals enable us to solve minimization problems of the type just described by the simplex method Finite Maths

  46. Objective function Duality • Construct the dual of this problem: get solution back transpose Finite Maths

  47. Duality (cont) duals duals Finite Maths

  48. Duality (cont) duals Finite Maths

  49. Duality (cont) Finite Maths

  50. Duality (cont) • Theorem of Duality: “The objective function w of a minimizing linear programming problem takes on a minimum value if and only if the objective function z of the corresponding dual maximizing problem takes on a maximum value. The maximum value of z equals the minimum value of w” Finite Maths

More Related