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Solving Series circuits How to Whiteboards

In this guide, we explore series circuits by examining voltage drops and current flow. A series circuit always has the same current flowing through all components, while voltages differ. We will calculate total resistance, current, and voltage drops for different component configurations using Ohm's Law (V = IR). Examples include finding the total resistance in different resistor combinations and deriving voltmeter readings. Through practical applications and analogies, you will deepen your understanding of electrical principles in series circuits.

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Solving Series circuits How to Whiteboards

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  1. Solving Series circuits • How to • Whiteboards

  2. A Series Circuit has many voltages, but only one current A1 Note that the total voltage drops add to source voltage 1  V1 = IR = (3 A)(1 ) = 3 V V1 24 V V2 = IR = (3 A)(2 ) = 6 V 2  V2 A2 V3 = IR = (3 A)(5 ) = 15 V 5  V3 A3 • How to solve series: • 1. Find the total resistance (1  + 2  + 5  = 8) • 2. Find the one current (I = V/R = (24 V)/(8 ) = 3 A - all • the ammeters read 3 A) • 3. Use V = IR to find voltages (voltage drops)

  3. I A1 A2 R1 R2 R3 • Analogy - ping pong balls - electrons • All start moving at once/speed of impulse, speed of particles • Resistance anywhere along the tube limits flow everywhere

  4. Whiteboards 1 | 2 | 3 | 4

  5. What is the Total resistance? 11  7  5  20.0 V R tot = R1 + R2 + R3 ... = 5  + 7  + 11  = 23  23 

  6. What is the reading on both ammeters? (The one current) (answer with 3 SF) 11  5  7  A2 A1 20 V I = V/R = (20 V)/(23 ) = .8696 = .870 A .870 A

  7. What do the voltmeters read? (3 SF) V1 V2 11  7  5  20.0 V V = IR V1 = (5 )(.8696 A) = 4.35 V V2 = (18 )(.8696 A) = 15.7 V 4.35 V, 15.7 V

  8. What do the voltmeters read? (3 SF) V1 V2 11  9  5  35 V 13  3  R = 41 , I = .8537 A V = IR V1 = (5 )(.8537 A) = 4.27 V V2 = (20 )(.8537 A) = 17.1 V V3 = (13 )(.8537 A) = 11.1 V V3 4.27 V, 17.1 V, 11.1 V

  9. What do the voltmeters read? (3 SF) V1 V2 200  90  500  V3 110  120 V 130  R = 1030 , I = .1165 A V = IR V1 = (500 )(.1165 A) = 58.3 V V2 = (90 )(.1165 A) = 10.5 V V3 = (330 )(.1165 A) = 38.4 V 58.3 V, 10.5 V, 38.4 V

  10. What is the value of the mystery resistor if V1 reads 3.17 V (3 SF) V1 ???  7  5  20 V I = V/R = (3.17 V)/(5 )= .634 A Rtot = V/I = (20 V)/(.634 A) = 31.55  Rtot = 5  + 7  + ?? = 31.55  ?? = 19.5  19.5 

  11. V3 A3

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