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Clase 54

Clase 54. Ejercicios sobre cálculo trigonométrico. 3 A + 2 B. D  C.  3. –. =. 3. Revisión del estudio individual. Ejercicio7,inciso b, página 184, L.T. 10 mo grado. Si A = tan 150 0 ; B = cos 210 0 ; C = sen 315 0 y D = cos0 0. Calcula:. A = tan 150 0.

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Clase 54

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  1. Clase 54 Ejercicios sobre cálculo trigonométrico.

  2. 3A + 2B D C 3 – = 3 Revisión del estudio individual Ejercicio7,inciso b, página 184, L.T. 10mogrado. Si A = tan 1500; B = cos 2100; C = sen 3150 y D = cos00. Calcula: A = tan 1500 = tan(1800 – 300) =– tan 300

  3. – = – = –  2  3  2 2 2 2 3A + 2B D C 1 3 3 – – 3 2 B = cos 2100 = cos (1800+ 300 ) = – cos300 C = sen 3150=sen (3600–450) =– sen 450 D = cos 00 = 1 3 + 2 =

  4.  2  2 – 4 3 – 2 3A + 2B D C –2 3 = – 2 2  = = 2 6

  5. D 1 = B A – C Ejercicio 1 Sean: A = cos 600 B = tan 450, y C = sen 3300. Demuestra que D =1 si :

  6. 1 1 1 1 1 1 2 2 2 2 2 2 D 1 = = + – B A – C A= cos 600 = B = tan450=1 C = sen 3300 = sen(3600 – 300) = –sen300= – – A – C = = 1 por tanto D = 1

  7. Ejercicio 2 : 8 sen2 1200 + 3cos 1800 a) tan 600 2 2,5 sen 900 –tan 450 + b) cos 2400 cos 3600 Calcula el valor numérico de las siguientes expresiones:

  8. √3 8( ) 2 +3(- 1) 2 = a) 8 sen2 1200+ 3cos 1800 √3 tan 600 3 ) 8( - 3 4 = √3 √3 3 3 √3 3 √3 1,73 = = = √3 √3 √3 2 3 1200 IIC 2 seno :+ F.R: 1200=1800 –  = 600 = sen 1200 = sen 600

  9. 2 b) 2,5 sen 900 –tan 450 + cos 3600 cos 2400 1 = – 2 2400 IIIC  coseno : –  F.R: 2400 = 1800 +   = 600 cos 2400 = –cos600  –cos600

  10. 2 1 – 1 2 b) 2,5 sen 900 –tan 450 2 + 5 1 = cos 3600 cos 2400 2,5(1) √1 + = + 2 = – 4

  11. sen a + cos b 2 cos d tan2c 2 √2 Para el estudio individual Prueba que: = Si conoces que: a= 1500 ;b =  ; c = 450 y d =2250

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