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3.2 Linear Programming

3.2 Linear Programming. 3 Credits AS 91574. Linear Programming. Learning objectives. I can plot linear equations I can find the points of intersection. try these. Draw axes with x from -4 to 4 and y from -8 to 6 Then plot the following graphs on the same axes…

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3.2 Linear Programming

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  1. 3.2 Linear Programming 3 Credits AS 91574

  2. Linear Programming Learning objectives • I can plot linear equations • Ican find the points of intersection

  3. try these... Draw axes with x from -4 to 4 and y from -8 to 6 Then plot the following graphs on the same axes… a) y=3x-4 b) y=2x+1

  4. You need 3 points to plot a straight a good start can be x = 0 and y = 0 for y = 2x + 1 this gives (0, 1) , (-0.5 , 0) and at random choose x = 1 (1, 3) with y = 3x - 4 (0, -4) , (-1.3, 0) and (1, -1)

  5. y 10 9 8 7 6 5 4 3 2 1 x 0 -10 1 2 3 4 5 6 7 9 10 -9 -8 -6 -4 -3 -2 8 -7 -5 -1 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 y = 2x + 1 y = 3x – 4

  6. This time you need to rearrange the formula first (unless you can do it in your head?) a good start can be x = 0 and y = 0 for 2y = x + 10 rearranges to y = 0.5x + 5 which gives (0, 5) , (-10 , 0) and (almost) at random choose x = 2 (2, 7) with 0.5y = x – 2.5 rearrange to get y = 2x - 5 (0, -5) , (-2.5, 0) and (3, 1)

  7. y 10 9 8 7 6 5 4 3 2 1 x 0 -10 1 2 3 4 5 6 7 9 10 -9 -8 -6 -4 -3 -2 8 -7 -5 -1 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 y = ½x + 5 y = 2x - 5

  8. Finding points of intersection use your calculator! select Equations, Simultaneous and two unknowns just like you did for 3.15!  188x + 290y = 2315 120x + 400y = 1800 should give you x = 10 and y = 1.5

  9. Success Criteria • I can plot linear equations • Nulake page 5 – 6 • work sheet • I can find the points of intersection

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