1 / 21

Chapter 22 – Alternating Current Part 2

PHY-2054 J. B. Bindell. Chapter 22 – Alternating Current Part 2. Monday – Continue with Chapter 22 Wednesday – Hope to return the exams. more of the same Friday – Quiz No 10:30 AM office hours (sorry)

mdragon
Télécharger la présentation

Chapter 22 – Alternating Current Part 2

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. PHY-2054 J. B. Bindell Chapter 22 – Alternating CurrentPart 2

  2. Monday – Continue with Chapter 22 • Wednesday – • Hope to return the exams. • more of the same • Friday – • Quiz • No 10:30 AM office hours (sorry) • Next Monday – Probably a problem solving session at 7:00AM. Confirmation later in the week. the future

  3. result - inductor I is the MAXIMUM current in the circuit.

  4. Resistor inductor (wL) looks like a resistance XL=wL Reactance - OHMS comparing

  5. For the inductor FOR THE RESISTOR Let’s put these together.

  6. slightly confusing point We will always use the CURRENT as the basis for calculations and express voltages with respect to the current. What that means?

  7. the phasor

  8. direction wt wt

  9. remember for ac series circuits The current is the same throughout the series circuit. The Maximum Current “I” is also the same for all series circuit elements.

  10. Compute the reactance of a 0.450 H inductor at frequencies of 60.0 Hz

  11. In the circuit below, R=30 W and L= 30 mH. If the angular frequency • of the 60 volt AC source is is 3 K-Hz • WHAT WE WANT TO DO: • calculate the maximum current in the circuit • calculate the voltage across the inductor • Does Kirchoff’s Law Work? E=60V w=3 KHZ R=30 W L= 30 mH

  12. R=30W XL=wL=90W The instantaneous voltage across each element is the PROJECTION of the MAXIIMUM voltage onto the horizontal axis! This is the SAME as the sum of the maximum vectors projected onto the horizontal axis. E=60V I w=3 KHZ R=30 W L= 30 mH wt

  13. Source voltage leads the current by the angle f. I wt E=60V w=3 KHZ R=30 W L= 30 mH

  14. The drawing is obviously NOT to scale. I wt E=60V w=3 KHZ R=30 W L= 30 mH

  15. What about the capacitor?? Without repeating what we did, the question is what function will have a Df/Dt = cosine? Obviously, the sine! So, using the same process that we used for the inductor,

  16. capacitorphasordiagram

  17. The voltage lags the current by 90 deg I and V are represented on the same graph but are different quantities. NOTICE THAT

  18. SUMMARY

  19. An AC source with ΔVmax = 125 V and f = 25.0 Hz is connected between points a and d in the figure. Calculate the maximum voltages between the following points: (a) a and b 62.8 V(b) b and c 45.6 V(c) c and d 154 V(d) b and d 108 V

  20. ac circuits look complicated http://www.ngsir.netfirms.com/englishhtm/RLC.htm

More Related