1 / 6

Parabolas (part 2)

Parabolas (part 2). I. Vertex form of a Parabola. A) (x – h) 2 = a(y – k) or (y – k) 2 = a(x – h) 1) Vertex is at (h , k) [Change the signs] B) You will need to be able to complete the square and factor to get an equation into Vertex form.

monico
Télécharger la présentation

Parabolas (part 2)

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Parabolas (part 2) I. Vertex form of a Parabola. A) (x – h)2 = a(y – k) or (y – k)2 = a(x – h) 1) Vertex is at (h , k) [Change the signs] B) You will need to be able to complete the square and factor to get an equation into Vertex form. C) You can find the focus easily from the Vertex form. 1) Divide the “a” by 4. The squared term gets the 0. 2) Add this value to the Vertex point (h , k) to get the focus point. Vertex (x , y) + Focus (0 , #) or (# , 0).

  2. Parabolas (part 2) II. Completing the Square [ ½ the #, square the # ]. A) Complete the square on the squared term only. 1) Make the equation say 1x2 or 1y2. a) Divide/Multiply everything to make coefficient = 1. 2) Move everything except the x2 + bx or the y2 + by terms to the other side of the = sign. 3) Complete the square: ½ the number, square that #. a) x2 + bx  (x + b/2)2 = … + (b/2)2 -- or -- y2 + by  (y + b/2)2 = … + (b/2)2 4) Collect like terms on the non-squared side.

  3. Parabolas (part 2) III. Factoring the Non-Squared Side. A) After you have collected like terms on the non-squared side, factor out the number in front of the non-squared term from both numbers on that side of the = sign. 1) (x – h)2 = ay + b  (x – h)2 = a(y + b/a) B) The equation is now in Vertex form. 1) (x – h)2 = a(y + b/a) or (y – k)2 = a(x + b/a) C) Finding the focus point. 1) Divide the “a” term by 4 ( or multiply by ¼ ). 2) The squared term gets the 0, the non-squared term gets the focus value. 3) Add the focus (0 , #) or (# , 0) to the vertex’s (x , y) to get the coordinates of the focus.

  4. Parabolas (part 2) IV. Graphing the Parabola in Vertex Form. A) If the equation is in Vertex form [ vertex is (h , k) ]. 1) (x – h)2 = a(y – k) or (y – k)2 = a(x – h) B) Ignore (erase) the sideways & up/down shift values. Only keep the “a” term. C) Get the equation into y = ax2 or x = ay2 form. 1) You will have to divide by the “a” term to move it. D) Determine the direction the parabola will open and if it should be taller (a>1 = narrow) or shorter (0>a>1 = wider). Examples: (x – 3)2 = 5(y + 1) (y + 6)2 = ½(x – 4) Ignore the shifts x2 = 5y y2 = ½x Move the “a” term 1/5x2 = y 2y2 = x Determine the shape wide-opens upward narrow-opens right

  5. Parabolas (part 2) Examples: x2 + 4x – 12y + 40 = 0 (x2 + 4x) = 12y – 40 (x + 2)2 = 12y – 40 + (2)2 [ ½ the # , #2 ] (x + 2)2 = 12y – 36 (x + 2)2 = 12(y – 3) Vertex = (–2 , 3) Focus is 12/4 = 3  so y = +3. so Focus = (–2 , 3+3) = (–2 , 6) Eq: 12y = x2 y = 1/12x2

  6. Parabolas (part 2) Examples: 3y2 – 18y + 6x – 12 = 0 [divide everything by 3] y2 – 6y + 2x – 4 = 0 [move non-y terms over] (y2 – 6y) = –2x + 4 (y – 3)2 = –2x + 4 + (3)2 [ ½ the # , #2 ] (y – 3)2 = –2x + 13 (y – 3)2 = –2(x – 13/2) Vertex = (13/2 , 3) or (6.5 , 3) Focus is –2/4 = –½  so x = –.5 so Focus = (6.5 – .5 , 3) = (6 , 3) Eq: –2x = y2 x = –½ y2

More Related