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Hybrid Dense /Sparse Matrices in Compressed Sensing Reconstruction. Ilya Poltorak Dror Baron Deanna Needell. The work has been supported by the Israel Science Foundation and National Science Foundation. CS Measurement.
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Hybrid Dense/Sparse Matrices in Compressed Sensing Reconstruction Ilya Poltorak Dror Baron Deanna Needell The work has been supported by the Israel Science Foundation and National Science Foundation.
CS Measurement • Replace samples by more general encoderbased on a few linear projections (inner products) sparsesignal measurements # non-zeros
Caveats • Input x strictly sparse w/ real values • Noiseless measurements • noise can be addressed (later) • Assumptions relevant to content distribution (later)
Why is Decoding Expensive? Culprit: dense, unstructured sparsesignal measurements nonzeroentries
Sparse Measurement Matrices (dense later!) • LDPC measurement matrix (sparse) • Only {-1,0,+1} in • Each row of contains L randomly placed nonzeros • Fast matrix-vector multiplication • fast encoding & decoding sparsesignal measurements nonzeroentries
Example 0 1 1 4 ? ? ? ? ? ? 0 1 1 0 0 0 0 0 0 1 1 0 1 1 0 0 1 0 0 0 0 0 1 1
Example • What does zero measurement imply? • Hint: x strictly sparse 0 1 1 4 ? ? ? ? ? ? 0 1 1 0 0 0 0 0 0 1 1 0 1 1 0 0 1 0 0 0 0 0 1 1
Example • Graph reduction! 0 1 1 4 ? 0 0 ? ? ? 0 1 1 0 0 0 0 0 0 1 1 0 1 1 0 0 1 0 0 0 0 0 1 1
Example • What do matching measurements imply? • Hint: non-zeros in x are real numbers 0 1 1 4 ? 0 0 ? ? ? 0 1 1 0 0 0 0 0 0 1 1 0 1 1 0 0 1 0 0 0 0 0 1 1
Example • What is the last entry of x? 0 1 1 4 0 0 0 0 1 ? 0 1 1 0 0 0 0 0 0 1 1 0 1 1 0 0 1 0 00 00 1 1
Noiseless Algorithm[Luby & Mitzenmacher 2005] [Sarvotham, Baron, & Baraniuk 2006][Zhang & Pfister 2008] Phase1:zero measurements Initialize Phase2: matchingmeasurements typically iterate 2-3 times Phase3: singleton measurements Arrange output Done? yes no
Numbers (4 seconds) • N=40,000 • 5% non-zeros • M=0.22N • L=20 ones per row • Only 2-3 iterations iteration #1
Challenge • With measurements parts of signal still not reconstructed • How do we recover the rest of the signal?
Solution: Hybrid Dense/Sparse Matrix • With measurements parts of signal still not reconstructed • Add extra dense measurements • Residual of signal w/ residual dense columns residual columns
Sudocodes with Two-Part Decoding[Sarvotham, Baron, & Baraniuk 2006] • Sudocodes (related to sudoku) • Graph reduction solves most of CS problem • Residual solved via matrix inversion Residual via matrix inversion sudo decoder residual columns
Contribution 1: Two-Part Reconstruction • Many CS algorithms for sparse matrices [Gilbert et al., Berinde & Indyk, Sarvotham et al.] • Many CS algorithms for dense matrices [Cormode & Muthukrishnan, Candes et al., Donoho et al., Gilbert et al., Milenkovic et al., Berinde & Indyk, Zhang & Pfister, Hale et al.,…] • Solve each part with appropriate algorithm sparse solver residual via dense solver residual columns
Theoretical Results [Sarvotham, Baron, & Baraniuk 2006] • Fast encoder and decoder • sub-linear decoding complexity • caveat: constructing data structure • Distributed content distribution • sparsified data • measurements stored on different servers • any M measurements suffice • Strictly sparse signals, noiseless measurements
Contribution 2: Noisy Measurements • Results can be extended to noisy measurements • Part 1 (zero measurements): measurement |ym|< • Part 2 (matching): |yi-yj|< • Part 3 (singleton): unchanged
Problems with Noisy Measurements • Multiple iterations alias noise into next iteration! • Use one iteration • Requires small threshold (large SNR) • Contribution 3:Provable reconstruction • deterministic & random variants
Summary • Hybrid Dense/Sparse Matrix • Two-part reconstruction • Simple (cute?) algorithm • Fast • Applicable to content distribution • Expandable to measurement noise