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Quantum Physics Part 1

Quantum Physics Part 1. AP Physics – J. Ruffolo , Ph.D. Planck’s Equation:. E = hf ( h = 6.626 x 10 -34 J s). Photon. E = hf. Plank’s Constant. In his studies of black-body radiation, Maxwell Planck discovered that electromagnetic energy is emitted or absorbed in discrete quantities.

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Quantum Physics Part 1

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  1. Quantum Physics Part 1 AP Physics – J. Ruffolo, Ph.D.

  2. Planck’s Equation: E = hf (h = 6.626 x 10-34 J s) Photon E = hf Plank’s Constant In his studies of black-body radiation, Maxwell Planck discovered that electromagnetic energy is emitted or absorbed in discrete quantities. Apparently, light consists of tiny bundles of energy called photons, each having a well-defined quantum of energy.

  3. 1 eV = 1.60 x 10-19 J 1 keV = 1.6 x 10-16 J 1 MeV = 1.6 x 10-13 J Energy in Electron-volts Photon energies are so small that the energy is better expressed in terms of the electron-volt. One electron-volt (eV)is the energy of an electron when accelerated through a potential difference of one volt.

  4. E = 2.24 eV Or Since 1 eV = 1.60 x 10-19 J Example 1:What is the energy of a photon of yellow-green light (l = 555 nm)? First we find ffrom wave equation: c = fl E = 3.58 x 10-19 J

  5. Useful Energy Conversion Since light is often described by its wavelength in nanometers (nm) and its energy Eis given in eV, a conversion formula is useful. (1 nm = 1 x 10-9m) If lis in nm, the energy in eV is found from: Verify the answer in Example 1 . . .

  6. Incident light Cathode Anode A C Ammeter A + - The Photo-Electric Effect When light shines on the cathode C of a photocell, electrons are ejected from A and attracted by the positive potential due to battery. There is a certain threshold energy, called the work function W, that must be overcome beforeany electrons can be emitted.

  7. Incident light Cathode Anode A C Ammeter Threshold wavelength lo A + - Photo-Electric Equation The conservation of energy demands that the energy of the incoming light hc/l be equal to the work function Wof the surface plus the kinetic energy ½mv2of the emitted electrons.

  8. l = 600 nm A K = 1.10 x 10-19 J Or Example 2:The threshold wavelength of light for a given surface is 600 nm. What is the kinetic energy of emitted electrons if light of wavelength 450 nm shines on the metal? ; K = 2.76 eV – 2.07 eV K = 0.690 eV

  9. Incident light Cathode Anode The stopping potential is that voltage Vo that just stops the emission of electrons, and thus equals their original K.E. V A + - Potentiometer Photoelectric equation: Stopping Potential A potentiometer is used to vary to the voltage V between the electrodes. Kmax = eVo

  10. The slope of a line: y Slope xo x y x Slope of a Straight Line (Review) The general equation for a straight line is: y = mx + b The x-intercept xo occurs when line crosses x axis or when y = 0. The slope of the line is the rise over the run:

  11. Finding h constant Stopping potential V Slope y x fo Frequency Finding Planck’s Constant, h Using the apparatus on the previous slide, we determine the stopping potential for a number of incident light frequencies, then plot a graph. Note that the x-intercept fo is the threshold frequency.

  12. Stopping potential V Slope y fo x Frequency Example 3:In an experiment to determine Planck’s constant, a plot of stopping potential versus frequency is made. The slope of the curve is 4.13 x 10-15 V/Hz. What is Planck’s constant? h = e(slope) = (1.6 x 10-19C)(4.13 x 10-15 V/Hz) Experimental Planck’s h = 6.61 x 10-34 J/Hz

  13. Incident light Cathode Anode A V + - Stopping potential: Vo= 0.800 V Example 4:The threshold frequency for a given surface is 1.09 x 1015 Hz. What is the stopping potential for incident light whose photon energy is 8.48 x 10-19 J? Photoelectric Equation: W = (6.63 x 10-34 Js)(1.09 x 1015 Hz) =7.20 x 10-19 J

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