1 / 15

Section 4.1 Inequalities & Applications

Section 4.1 Inequalities & Applications. Equations 3x + 7 = 13 |y| = 7 3x + 2y = 6. Inequalities 3x + 7 < 13 |y| > 7 3x + 2y ≤ 6 Symbols: < > ≤ ≥ ≠. Overview of Linear Inequalities. 4.1 Study Inequalities with One Variable Why study Inequalities?

ugo
Télécharger la présentation

Section 4.1 Inequalities & Applications

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Section 4.1Inequalities & Applications • Equations • 3x + 7 = 13 • |y| = 7 • 3x + 2y = 6 • Inequalities • 3x + 7 < 13 • |y|>7 • 3x + 2y ≤6 • Symbols: • < > ≤ ≥ ≠ 4.1

  2. Overview of Linear Inequalities • 4.1 Study Inequalities with One Variable • Why study Inequalities? • How do we show a Solution to an Inequality • With an Algebraic Statement -5 < x x ≤11 |x -1| < 3 • ByGraphing Using the Number Line • UsingInterval Notation (-5, ∞) (- ∞, 11] (-∞,-2)U(2,∞) • ViaSet-Builder Notation { x | x > -5} {x | -4 <x ≤13 } • Use Properties to Solve Single-Variable Inequalities ( 4.1

  3. Solving Inequalities • Examples of Inequalities containing a variable -2 < a x > 4 x + 3 ≤ 6 6 – 7y ≥ 10y – 4 6 < x + 2 < 9 • A solution is a value that makes an inequality trueA solution set is the set of all solutions • Substitute a value to see if it is a solution: • Is 5 a solution to x + 3 < 6 no, 8 < 6 is false • Is -1a solution to -3 > -5 – 2x no, -3 > -3 false • Is 2 a solution to y + 2 ≥ 4 yes, 4 ≥ 4 is true 4.1

  4. Showing an Inequality Solutionon the Number Line • Identify the Boundary Point on the number line • Left ( or Right ) : the number is nota solution • Left [ or Right ] : the number is a solution • Shade the number line over all solutions ) 4.1

  5. Interval Notation • Is a compact way to precisely specify a complete solution set over a range of numbers, without reference to a variable name • Parentheses ( ) and Brackets [ ] have another use • They are used to enclose a pair of values • The smallest number is always listed on the left • They have the same meaning as used in graphing: point included or excluded • Examples: (2, 5) [0, 15) (-4, -2] [-22, 43] • (-∞, 7) and [3, ∞) show how infinity values are noted • Interval notation can be used in addition to Set-builder 4.1

  6. Example:Number Line Graphs and Notation • What is the inequality for all real numbers greater than -5? • Either of the algebraic statements x > -5 or -5 < x • Set-builder Notation (using the inequality) can also be used{ x | -5 < x } • We can also show this interval in Interval Notationas (-5, ∞) • We can graph this by identifying a portion of the number line.Any portion of a number line is called an intervalFor example, all real numbers greater than -5 up to ∞ is graphed ( 4.1

  7. Unbounded Intervals ( point not included [ point is included ( or ) [ or ] ( a [ a ) a ] a a Some textbooks use a hollow dot ○ in place of ( or ) and a solid dot ● in place of [ or ] 4.1

  8. Principles Used to Solve Inequalities • Addition (and Subtraction) Principles • Any real number (or term) can be added to (or subtracted from) both sides of an inequality to produce another inequality with the same solutions.The direction of the inequality symbol is unchanged. • a < b is equivalent to a + c < b + c (true for >, ≥, < and ≤ ) Example 4 – Solve and graph • x + 5 > 1 x > -4 (-4,∞) {x| x>-4} • 4x – 1 ≥ 5x – 2 1 ≥ x (-∞,1] {x| x≤1} 4.1

  9. Principles Used to Solve Inequalities • Positive Multiplication (and Division) Principles • If both sides of an inequality are multiplied (or divided) by a positive number, the new inequality will have the same solutions.The direction of the inequality symbol is unchanged. • a < b is equivalent to a • c < b • c (true for >, ≥, < and ≤ ) Example 5 – Solve and graph • 3y < ¾ y < ¼ (-∞,¼) {y| y<¼} • ½t ≥ 5 t ≥ 10 [10,∞) {t| t≥10} 4.1

  10. Principles Used to Solve Inequalities • Negative Multiplication (and Division) Principles • If both sides of an inequality are multiplied or divided by a negative number, the new inequality will be equivalentonly if the direction of the inequality symbol is reversed! • Consider 5 < 7 Let’s multiply by -1: (-1)5 < (-1)7 … is -5 < -7 ? • No! -5 > -7 so remember to reverse the symbol Example 5 – Solve and graph • -5y < 3.2 y > -0.64 (-0.64,∞) {y| y>-0.64} • - ¼x ≥ -80 x ≤ 320 (-∞,320] {x| x≤320} 4.1

  11. Principles Used Together • As in equations, • First use the addition principle to move variable terms to one side and numeric terms to the other • Then use the multiplication principle to effect the solution Example 6 – Solve and graph • 16 + 7y ≥ 10y – 2 y ≤ 6 (-∞,6] {y| y ≤ 6 } • -3(x + 8) – 5x > 4x – 12 x < 1 (-∞,1) {x| x < 1 } 4.1

  12. Class Practice • Use the properties of linear inequalities to solve the following and graph the solution set. Also give the solution in interval notation. • –2y + 6 ≤ –2 –2y ≤ – 8 y ≥ 4 [4,∞) • -9(h – 3) + 2h <8(4 –h) [ 4.1

  13. Problem Solving • The statements“a does not exceed b”and“a is at most b”both translate to the inequalitya ≤ b • The statements“a is at least b”and“a is no less than b”both translate to the inequalitya ≥ b 4.1

  14. Applications • Truck Rentals. Campus Fun rents a truck for $45 plus 20¢ per mile. Their rental budget is $75. For what mileages will they NOT exceed their budget? • “for ____ miles or less” or“mileage less than or equal to ____” • Charges = f(m) = 45 + .20m • 45 + .20m ≤ 75 150 150 4.1

  15. What Next? • Section 4.2 –Intersections, Unions & Compound Inequalities 4.1

More Related