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Chapter 7

Chapter 7. 7-3 Triangle similarity. Objectives. Prove certain triangles are similar by using AA, SSS, and SAS. Use triangle similarity to solve problems. Triangle similarity.

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Chapter 7

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  1. Chapter 7 7-3 Triangle similarity

  2. Objectives • Prove certain triangles are similar by using AA, SSS, and SAS. • Use triangle similarity to solve problems.

  3. Triangle similarity • There are several ways to prove certain triangles are similar. The following postulate, as well as the SSS and SAS Similarity Theorems, will be used in proofs just as SSS, SAS, ASA, HL, and AAS were used to prove triangles congruent.

  4. Since , B  E by the Alternate Interior Angles Theorem. Also, A  D by the Right Angle Congruence Theorem. Therefore ∆ABC ~ ∆DEC by AA~. Example 1: Using the AA Similarity Postulate • Explain why the triangles are similar and write a similarity statement.

  5. Check it out! • Explain why the triangles • are similar and write a • similarity statement. By the Triangle Sum Theorem, mC = 47°, so C F. B E by the Right Angle Congruence Theorem. Therefore, ∆ABC ~ ∆DEF by AA ~.

  6. Triangle similarity

  7. Triangle similarity

  8. Example 2A: Verifying Triangle Similarity • Verify that the triangles are similar. ∆PQR and ∆STU Therefore ∆PQR ~ ∆STU by SSS ~.

  9. Example 2B: Verifying Triangle Similarity • Verify that the triangles are similar. Therefore ∆DEF ~ ∆HJK by SAS ~. D  H by the Definition of Congruent Angles.

  10. Example 3: Finding Lengths in Similar Triangles • Explain why ∆ABE ~ ∆ACD, and then find CD.

  11. Check it out • Explain why ∆RSV ~ ∆RTU and then find RT.

  12. Writing proofs • Given: 3UT = 5RT and 3VT = 5ST Prove: ∆UVT ~ ∆RST

  13. 2. 4. Solution 1. 3UT = 5RT 1. Given 2. Divide both sides by 3RT. 3. Given. 3. 3VT = 5ST 4. Divide both sides by3ST. 5.RTS VTU 5. Vert. s Thm. 6.∆UVT ~ ∆RST 6. SAS ~Steps 2, 4, 5

  14. Given: M is the midpoint of JK. N is the midpoint of KL, and P is the midpoint of JL. Check it out

  15. 1. M is the mdpt. of JK, N is the mdpt. of KL, and P is the mdpt. of JL. 2. 3. Solution 1. Given 2.∆ Midsegs. Thm 3. Div. Prop. of =. 4.∆JKL ~ ∆NPM 4. SSS ~ Step 3

  16. The photo shows a gable roof. AC || FG. ∆ABC ~ ∆FBG. Find BA to the nearest tenth of a foot. Application

  17. Solution • Therefore, BA = 23.3 ft.

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