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Chi squared

Chi squared . A biologist randomly selects 20 fruit flies. All of them are placed in a tube with vinegar on one side and mustard on the other side. Do these fruit flies have a preference for either mustard or vinegar? The results are listed below. mustard : 5 vinegar: 15 .

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Chi squared

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  1. Chi squared

  2. A biologist randomly selects 20 fruit flies. All of them are placed in a tube with vinegar on one side and mustard on the other side. Do these fruit flies have a preference for either mustard or vinegar? The results are listed below. mustard : 5 vinegar: 15 First name the test. χ2 Goodness of Fit Test.

  3. A biologist randomly selects 20 fruit flies. All of them are placed in a tube with vinegar on one side and mustard on the other side. Do these fruit flies have a preference for either mustard or vinegar? The results are listed below. mustard : 5 vinegar: 15 χ2 Goodness of Fit Test. Write the hypotheses Ho : Fruit flies are equally drawn to mustard and vinegar. Ha : Fruit flies are not equally drawn to mustard and vinegar.

  4. A biologist randomly selects 20 fruit flies. All of them are placed in a tube with vinegar on one side and mustard on the other side. Do these fruit flies have a preference for either mustard or vinegar? The results are listed below. mustard : 5 vinegar: 15 χ2 Goodness of Fit Test. Ho : The fruit flies are equally drawn to mustard and vinegar. Ha : The fruit flies are not equally drawn to mustard and vinegar. Conditions The fruit flies are randomly selected is given. Data are categorical (or counts). All expected values are ≥ 5. Expected counts for each group = 10

  5. Calculate χ2 Degrees of freedom = 2 – 1 = 1

  6. χ2 = 5 df= 1 .025 < p-value < .05

  7. Biology table for chi-squared critical value approach So how much proof do you need?

  8. χ2 Goodness of Fit Test. Ho : The fruit flies are equally drawn to mustard and vinegar. Ha : The fruit flies are not equally drawn to mustard and vinegar. Conditions The fruit flies are randomly selected is given. Data are categorical (or counts). All expected values are ≥ 5. Expected counts for each group = 10 χ2 = 5 > 3.84 df = 1 .025 < p-value < .05 Conclusion Reject Ho since the p-value < α = .05 (or since χ2 > critical value 3.84) We have evidence that fruit flies do have a preference. They appear to prefer vinegar over mustard. Ta Da!

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