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## Density

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**1 m3**1 liter 1 liter = 1 dm3 1 meter 1 dm3 1 decimeter**1 dm**1 dm 1 liter 1 dm**Imagine that we slice the cube into cm lengths.**How many cubes? 1000 cubes 1 mL = 1cm3 We would make smaller cubes the size of a cm. 1 mL = 1/1000 L 1 liter 1 dm = 10 cm**1000**= 1 liter**1 liter**1000 = 1 liter = 1 liter 1000 cm3 = 1000 mL 1 cm3 = 1 mL**It’s important that you know what a cm3 is.**And that a cm3 is also equal to a mL. Because density is the mass of 1 cm3 (or 1 mL) of a substance. 1 cm3 = 1mL = 1/1000 L**density = mass/volume**in grams in cm3 (or mL) density = # of grams/1 cm3 or density = x grams/cm3**Let’s look closer at the cubic centimeter.**1cm3 1cm3 1cm3 nickel iron water substance: 1 gram mass: 9 g 8 g 8 g/cm3 9 g/cm3 1g/cm3 density:**substance:**nickel iron water 8 g/cm3 9 g/cm3 density: 1g/cm3 16g 18g /2cm3 /2cm3 2g /2cm3 24g 27g /3cm3 /3cm3 3g /3cm3 4g/4cm3 32g/4cm3 36g/4cm3 40g/5cm3 5g/5cm3 45g/5cm3**If you plot the mass versus volume you get a linear graph.**The slope is the density. 48 44 40 36 32 Mass (grams) 28 24 20 water 16 iron nickel 12 1 ml,9g 8 1 ml,8g 5 ml,5g 4 ml,4g 3 ml,3g 4 2 ml,2g 1 ml,1g 0 1 2 3 4 5 6 Volume (mL)**The density of a substance doesn’t change even though you**have more of it. When you change the amount of the substance both the mass and volume change. If we had 12 cm3 of water, its mass would be 12 g. density = mass/volume = 12g/12 cm3 = 1g/cm3 still the same density**Sometimes you can identify a metal by its density.**For example, suppose we had a chunk of metal and we weren’t sure whether it was iron or nickel. They look the same. How can we tell whether the metal is nickel or iron? density of iron = 8g/mL density of nickel = 9g/ml If we can determine the density of the unknown metal, we can tell whether it’s iron or nickel.**To determine the density we need to know two properties of**the metal: M its mass _________ __ D = density = its volume V We would weigh it to get its mass.**If the metal was a rectangular solid, we could figure out**its volume by measuring the length, width, and height because . . . V = L x W x H 2cm V = 3cm x x 2cm V = 12cm3 = 12 3cm 2cm 2cm**Chances are though, the metal is not going to be a**rectangular solid. How do we determine the volume of this shape?**The volume of the metal is 12 mL.**84 mL 72 mL Water is added to a graduated cylinder. 12 mL**96.00 grams**= 8.0 g/mL or 8.0 g/cm3 density = 12 mL iron which makes it**Data Table**Mass of metal . . . . . . . . . . . . . . . . . . . 96.00 g Volume of water before submersion . . . . 72 mL Volume of water after submersion . . . . 84 mL