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Density

emmanuel-garrett avatar
emmanuel-garrett
44 diapositives · 673 Views · Nov 13, 2014

Density. Introduction. Introduction. We can see the difference in density of different materials when we look at ... wood floating on water helium balloons floating in the air. Introduction. We can see the difference in density of different materials when we look at ...

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  1. Density

  2. Introduction

  3. Introduction • We can see the difference in density of different materials when we look at ... • wood floating on water • helium balloons floating in the air

  4. Introduction • We can see the difference in density of different materials when we look at ... • iron sinking in water • lava lamps

  5. Introduction

  6. Properties

  7. Properties • Density is an intensive property of matter. • The density of matter does not depend on the amount of matter. • Density does depend on the composition of the matter

  8. m V D = Properties • Density is the mass of the matter divided by the volume of the matter. • The density of matter generally decreases as the temperature of the matter increases.

  9. Properties • The density of some materials is given in this chart:

  10. Properties

  11. Doing the Math

  12. m D m V D = V = Doing the Math • Density is the mass of the matter divided by the volume of the matter. • The volume of matter is the mass divided by the density. • The mass of matter is the density times the volume. m = D•V

  13. Doing the Math

  14. Examples

  15. Examples • Example 1:

  16. Examples • Example 1: • A block of wood has a length of 15 cm, a width of 10. cm, and a height of 5.0 cm. The block also has a mass of 340 g. What is the density of the block?

  17. Examples • Example 1: • A block of wood has a length of 15 cm, a width of 10. cm, and a height of 5.0 cm. The block also has a mass of 340 g. What is the density of the block? V = l•w•h = (15 cm)(10. cm)(5.0 cm)

  18. Examples • Example 1: • A block of wood has a length of 15 cm, a width of 10. cm, and a height of 5.0 cm. The block also has a mass of 340 g. What is the density of the block? V = l•w•h = (15 cm)(10. cm)(5.0 cm) = 750 cm3

  19. Examples • Example 1: • A block of wood has a length of 15 cm, a width of 10. cm, and a height of 5.0 cm. The block also has a mass of 340 g. What is the density of the block? V = l•w•h = (15 cm)(10. cm)(5.0 cm) = 750 cm3 m D = V

  20. Examples • Example 1: • A block of wood has a length of 15 cm, a width of 10. cm, and a height of 5.0 cm. The block also has a mass of 340 g. What is the density of the block? V = l•w•h = (15 cm)(10. cm)(5.0 cm) = 750 cm3 m 340 g D = = V 750 cm3

  21. Examples • Example 1: • A block of wood has a length of 15 cm, a width of 10. cm, and a height of 5.0 cm. The block also has a mass of 340 g. What is the density of the block? V = l•w•h = (15 cm)(10. cm)(5.0 cm) = 750 cm3 m 340 g D = = = 0.453333333 g/cm3 V 750 cm3

  22. Examples • Example 1: • A block of wood has a length of 15 cm, a width of 10. cm, and a height of 5.0 cm. The block also has a mass of 340 g. What is the density of the block? V = l•w•h = (15 cm)(10. cm)(5.0 cm) = 750 cm3 m 340 g D = = = 0.453333333 g/cm3 = 0.45 g/cm3 V 750 cm3

  23. Examples • Example 1: • A block of wood has a length of 15 cm, a width of 10. cm, and a height of 5.0 cm. The block also has a mass of 340 g. What is the density of the block? V = l•w•h = (15 cm)(10. cm)(5.0 cm) = 750 cm3 m 340 g D = = = 0.453333333 g/cm3 = 0.45 g/cm3 V 750 cm3

  24. Examples

  25. Examples • Example 2:

  26. Examples Example 2: A block of lead has a mass of 37.4 g. Lead has a density of 11.4 g/cm3. What is the volume of the block?

  27. Examples Example 2: A block of lead has a mass of 37.4 g. Lead has a density of 11.4 g/cm3. What is the volume of the block? m D = V

  28. Examples Example 2: A block of lead has a mass of 37.4 g. Lead has a density of 11.4 g/cm3. What is the volume of the block? m m D = ➔ V = V D

  29. Examples Example 2: A block of lead has a mass of 37.4 g. Lead has a density of 11.4 g/cm3. What is the volume of the block? m m 37.4 g D = ➔ V = = V D 11.4 g/cm3

  30. Examples Example 2: A block of lead has a mass of 37.4 g. Lead has a density of 11.4 g/cm3. What is the volume of the block? m m 37.4 g D = ➔ V = = = 3.280701754 cm3 V D 11.4 g/cm3

  31. Examples Example 2: A block of lead has a mass of 37.4 g. Lead has a density of 11.4 g/cm3. What is the volume of the block? m m 37.4 g D = ➔ V = = = 3.280701754 cm3 V D 11.4 g/cm3 V = 3.28 cm3

  32. Examples Example 2: A block of lead has a mass of 37.4 g. Lead has a density of 11.4 g/cm3. What is the volume of the block? m m 37.4 g D = ➔ V = = = 3.280701754 cm3 V D 11.4 g/cm3 V = 3.28 cm3

  33. Examples

  34. Examples • Example 3:

  35. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l

  36. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l

  37. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l = π(0.05000 cm)2(20.0 cm)

  38. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l = π(0.05000 cm)2(20.0 cm) = 0.157 cm3

  39. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l = π(0.05000 cm)2(20.0 cm) = 0.157 cm3 m D = V

  40. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l = π(0.05000 cm)2(20.0 cm) = 0.157 cm3 m D = ➔ V

  41. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l = π(0.05000 cm)2(20.0 cm) = 0.157 cm3 m D = ➔ m = D•V V

  42. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l = π(0.05000 cm)2(20.0 cm) = 0.157 cm3 m D = ➔ m = D•V = (8.86 g/cm3)(0.157 cm3) V

  43. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l = π(0.05000 cm)2(20.0 cm) = 0.157 cm3 m D = ➔ m = D•V = (8.86 g/cm3)(0.157 cm3) V m = 1.39 g

  44. Examples • Example 3: • What is the mass of a 20.0 cm length of copper wire with a density of 8.86 g/cm3 and a radius of 0.0500 cm? The volume of a cylinder is V = π•r2•l V = π•r2•l = π(0.0500 cm)2(20.0 cm) = 0.157 cm3 m D = ➔ m = D•V = (8.86 g/cm3)(0.157 cm3) V m = 1.39 g