SlideServe
Télécharger Obtenir Pro
Menu
Accueil Pro
Préférences
ApparenceLight Aide et commentaires
© SlideServe · v2026

30 Min Culvert Design

blake avatar
blake
21 diapositives · 1.6K Views · Mar 23, 2012

30 Min Culvert Design. Jered Carpenter Region 3 Roadway Design. Design Steps. Step 1) Gather hydrological & site specific data Step 2) Assume culvert size Step 3) Find headwater depth for trial size Step 4) Try another size Step 5) Compute outlet velocity

#civil engineering #stanford torus #via c3 #draft #mosaic #trap #seal #charge
30 Min Culvert Design - slide 1
01 / 2130 Min Culvert Design
1 / 17

Télécharger la présentation

30 Min Culvert Design
Une image / un lien ci-dessous est fourni (tel quel) pour télécharger la présentation

Politique de téléchargement : le contenu du site vous est fourni TEL QUEL pour votre information et votre usage personnel ; il ne peut être vendu, concédé sous licence ni partagé sur d’autres sites sans l’accord de son auteur.Le contenu vous est fourni TEL QUEL, pour votre information et votre usage personnel uniquement. Téléchargez la présentation en cliquant sur ce lien. Lors du téléchargement, si vous ne parvenez pas à télécharger une présentation, l’éditeur a peut-être supprimé le fichier de son serveur.Pendant le téléchargement, si vous ne parvenez pas à obtenir une présentation, le fichier a peut-être été supprimé par l’éditeur.

F I N

Plus de contenu associé

Transcription de la présentation

  1. 30 Min Culvert Design Jered Carpenter Region 3 Roadway Design

  2. Design Steps • Step 1) Gather hydrological & site specific data • Step 2) Assume culvert size • Step 3) Find headwater depth for trial size • Step 4) Try another size • Step 5) Compute outlet velocity • Step 6) Determine Invert Protection • Step 7) Document selection

  3. Del Rio Example

  4. Pictures of Existing Culvert

  5. Step 1) Gather Hydrological Data Q = cia = (.35*52*.82) = 14.9 cfs Zone 6 IDF Curve Culvert Location

  6. Step 1 Cont.) Site Specific Data • Invert In El. = 564.9’ • Invert Out El. = 564.5’ • Pipe Length = 75’ • Slope = -0.5%

  7. Step 1 Cont.) Site Specific Data • Calculate Tail Water, TW • 2.5’ btm, class 50 rip-rap lined FBD with 2:1 side slopes @ outlet • Manning’s Equation for discharge Q = (1.486/n)*A*R2/3S1/2 • Using a spreadsheet & setting Q as a function of depth, I get the following results when d=1.7 ft: 15.0 cfs = (1.486/0.07)*10.03ft2*0.99ft2/30.051/2 • TW = 1.7’

  8. Key #15186 – Del Rio “DR” 92+15 Jered Carpenter 11 Feb 08 1 of 1 Rational 52 Ac -0.5% Trapezoid 564.9 75 564.5 50 14.9 1.7 100 16.4 1.8

  9. Step 2) Assume Culvert Size Start With 18” Circular CMP

  10. Step 3) Find HW Depth For Trial Size • Assume inlet control • From Nomograph, HW/D = 3 • HW depth w/ inlet control approx. 569.4 ft., which is too high • I’ll try a 24” pipe

  11. Step 3) Find HW Depth For Trial Size • Assume inlet control • From Nomograph, HW/D = 1.2 • HW depth w/ inlet control approx. 566.7 ft., which is OK. • The 24” pipe looks good so far

  12. Key #15186 – Del Rio “DR” 92+15 Jered Carpenter 11 Feb 08 1 of 1 Rational 52 Ac -0.5% Trapezoid 564.9 75 564.5 50 14.9 1.7 100 16.4 1.8 CMP-Circ.-18”-Mitered 4.2 569.4 14.9 3.0 CMP-Circ.-24”-Mitered 14.9 1.2 2.4 567.3

  13. Step 3 Continued Check for outlet control • Need to calculate H, total outlet control head loss • Outlet control nomographs can be used if outlet crown is submerged. (TW>Top of Pipe @ Outlet) • TW @1.7’ < D @ 2’ , so I will not use the nomograph

  14. Step 3 Continued • Alternatively, H can be calculated by following the steps on the culvert design sheet • Calculate critical depth, dc • Critical depth = 1.4’ (from graph located in Chapter 8, appendix B)

  15. Step 3 Continued • Following Steps 4 thru 5 on the culvert design sheet: • (dc+D)/2 = (1.4’+2’)/2 = 1.7’ • ho = TW or (dc+D)/2 , whichever is greater TW @ 1.7’ = (dc+D)/2 @ 1.7’ ,use 1.7’

  16. Key #15186 – Del Rio “DR” 92+15 Jered Carpenter 11 Feb 08 1 of 1 Rational 52 Ac -0.5% Trapezoid 564.9 75 564.5 50 14.9 1.7 100 16.4 1.8 CMP-Circ.-18”-Mitered 4.2 569.4 14.9 3.0 CMP-Circ.-24”-Mitered 14.9 1.2 2.4 567.3 1.7 1.4 1.7 1.7

  17. Step 3 Continued • Calculate Energy losses, H for the culvert From the culvert design sheet: • H = (1+ke+(29*n2*L/R1.33))*(V2/2g) Ke = .7 (from table 9-3, mitered to slope) n = .024 (from table 8-A-2) L = 75’ Use values of V and R under full flow (d=2’) R = 0.5’ V = 4.74 ft/s (Average Velocity) • H = 1.52

  18. Step 3) Continued • Inlet Control HW Elevation = 567.3’ • Outlet Control HW Elevation = 567.9’ • The pipe flowing under outlet control.

  19. Step 4) Try Another Size • 24” pipe is acceptable. • Remainder of the Culvert design sheet is completed.

  20. Step 5) Compute Outlet Velocity • Previously calculated value. Determine if channel protection is required following the guidance in Chapter 11 of the hydraulics manual. Step 6) Determine Invert Protection • Follow guidance in Chapter 5 of the hydraulics manual to determine if & what type of invert protection is required.

  21. Step 7) Document Selection Key #15186 – Del Rio “DR” 92+15 Jered Carpenter 11 Feb 08 1 of 1 Rational 52 Ac -0.5% Trapezoid 564.9 75 564.5 50 14.9 1.7 100 16.4 1.8 CMP-Circ.-18”-Mitered 4.2 569.4 14.9 3.0 CMP-Circ.-24”-Mitered 14.9 1.2 2.4 567.3 1.7 1.4 1.7 1.7 1.7 1.7 567.9 567.9 4.74 Outlet Control Trap. Channel: W=2.5’ 2:1 side slopes N= .07 (class 50 rip rap) S=0.5% Dc=1.7’ 24” Circ. Metal 0.024 Mitered