1 / 7

Fireworks – Vertex Form of a Quadratic Equation

Fireworks – Vertex Form of a Quadratic Equation. • Recall that the standard form of a quadratic equation is. y = a · x 2 + b · x + c. where a , b , and c are numbers and a does not equal 0. • The vertex form of a quadratic equation is. y = a · ( x – h ) 2 + k.

Télécharger la présentation

Fireworks – Vertex Form of a Quadratic Equation

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Fireworks – Vertex Form of a Quadratic Equation • Recall that the standard form of a quadratic equation is y = a·x2 + b·x + c where a, b, and c are numbers and adoes not equal 0. • The vertex form of a quadratic equation is y = a·(x – h)2 + k where (h, k) are the coordinates of the vertex of the parabola and a is a number that does not equal 0.

  2. Fireworks – Vertex Form of a Quadratic Equation • Vertex form y = a·(x – h)2 + k allows us to find vertex of the parabola without graphing or creating a x-y table. y = (x – 2)2 + 5 a = 1 vertex at (2, 5) y = 4(x – 6)2 –3 a = 4 vertex at (6, –3) y = 4(x – 6)2 +–3 y = –0.5(x + 1)2 +9 a = –0.5 vertex at (–1, 9) y = –0.5(x – –1)2 +9

  3. Fireworks – Vertex Form of a Quadratic Equation • Check your understanding… 1. What are the vertex coordinates of the parabolas with the following equations? vertex at (4, 1) a. y = (x – 4)2 + 1 vertex at (–7, 3) b. y = 2(x + 7)2 + 3 vertex at (5, –12) c. y = –3(x – 5)2– 12 2. Create a quadratic equation in vertex form for a "wide" parabola with vertex at (–1, 8). y = 0.2(x + 1)2+ 8

  4. Fireworks – Vertex Form of a Quadratic Equation • Finding the a value. • Recall that the vertex form of a quadratic equation is y = a·(x – h)2 + k where (h, k) are the coordinates of the vertex of the parabola and a is a number that does not equal 0. Also, the values of x and y represent the coordinates of any point (x, y) that is on the parabola. • We can see that (2, 9) is a point on y = (x – 4)2 + 5 9 = (2 – 4)2 + 5 9 = 4 + 5 …because the equation is true 9 = 9

  5. Fireworks – Vertex Form of a Quadratic Equation • Finding the a value (cont'd) • If we know the coordinates of the vertex and some otherpoint on the parabola, then we can find the a value. • For example, What is the a value in the equation for a parabola that has a vertex at (3, 4) and an x-intercept at (7, 0)? y = a·(x – h)2 + k substitute 0 = a·(7 – 3)2 + 4 simplify 0 = a·(4)2 + 4 simplify 0 = a·16 + 4 subtract 4 -4 = a·16 divide by 16 -0.25 = a y = -0.25·(x – 3)2 + 4

  6. Fireworks – Vertex Form of a Quadratic Equation • Finding the a value (cont'd) What is the a value in the equation for a parabola that has a vertex at (2, -10) and other point at (3, -15)?

  7. Fireworks – Vertex Form of a Quadratic Equation • Classwork assignment • A particular parabola has its vertex at (-3, 8) and an x- • intercept at (1, 0). Your task is to determine which of • the following are other points on that same parabola. • 1. (-1, 6) • 2. (0, 3) • 3. (4, -16) • 4. (5, -24)

More Related