Chapter 16
This chapter explores the management of short-term assets, focusing on working capital and its components: current assets and current liabilities. It delves into the operating cycle and the importance of timing in cash flows, as well as financing strategies and their implications on working capital policy. Key concepts include the Economic Order Quantity (EOQ) for inventory management, Just-In-Time strategies, and the management of accounts receivable. Additionally, it touches on cash management techniques and money market instruments, emphasizing how organizations can optimize their financial resources.
Chapter 16
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Presentation Transcript
Chapter 16 Management of Short-term Assets
Preliminary Definitions • Working capital: Current (short-term) assets • Net working capital: Current assets minus current liabilities • Working capital policy: Management of current assets and current liabilities
The Operating Cycle • Time it takes to produce output, sell it, and collect payment • Timing of payments • Varies among industries • Affects the need for short-term finance
Financing and Working Capital Policy • Matching sources and uses of funds • Basic principle: do not use short-term sources to finance long-term assets • Cost structure of funds: • Long-term sources tend to be more expensive than short-term source
Aggressive Working Capital Policy • Use of more short-term sources • Increases profitability • Increases risk • But also increases the need to roll over or refinance short-term debt
Inventory Cycle • Inventory is • acquired • drawn down to some level • replenished • and the cycle is repeated • The safety stock
The Inventory Cycle $ B A T1 T2 Time
The Economic Order Quantity (EOQ) • Ordering costs versus carrying costs • Fewer orders reduce ordering costs but increases carrying costs
The Economic Order Quantity (EOQ) • The EOQ minimizes the sum of • Ordering costs (e.g., shipping and processing costs) plus • Carrying costs (e.g., warehouse expense, insurance, and interest expense)
The Economic Order Quantity (EOQ) • EOQ = (2SF/C).5 • EOQ = ((2 x 10,000 x $50)/$10).5 = 316
The Economic Order Quantity (EOQ) $ Costs A Total Costs E F Total Carrying Costs D $3,180 Total Ordering Costs B C 316 Order Size
The Inventory Cycle Combined with the EOQ Units of Inventory 366 Level of Inventory Safety Stock 50 0 5 10 15 Days
The Inventory Cycle Combined with the EOQ • Maximum inventory: EOQ plus the safety stock • Minimum inventory: Safety stock • Average inventory: EOQ/2 + safety stock
EOQ Model • A very simple model • Assumes • sales occur evenly • no quantity discounts • individual items are identifiable • Highlights the trade off between ordering costs and carrying costs
Just-in-Time inventory management • Designed to minimize the amount of inventory • Requires • accurate forecasts • excellent timing • dependable shipping • flexible schedules • frequent communication
Management of Accounts Receivable • Credit policy encompasses • Who will receive credit • Terms of credit • Collections
Decision to Grant Credit • Trade-off between additional sales versus additional costs • Additional costs • Cost of goods sold • Credit and collection costs • Bad debt expense • Carrying costs
Analyzing Accounts Receivable • Receivables turnover: Credit sales/Accounts receivable • Aging schedules: Determine payment patterns
Cash Management • Faster collections • Slower disbursements • Investing short-term funds
Facilitating Faster Collections • Electronic funds transfers • Lockbox
Money Market Instruments and Yields the Instruments • U.S. Treasury bills • Commercial paper • Negotiable certificates of deposit • Banker's acceptances • Eurodollar CDs • Repurchase agreements (REPOs)
Yields: the Discount Yield • Depends on • The principal amount • The amount of the discount • The time to maturityYd = Par value - Price x ________360_______ Par value Number of days to maturity
Yields: the Discount Yield • Yd = Par value - Price x ________360_______ Par value Number of days to maturity • $10,000 - $9,791 x _360_ = $10,000 180 4.18%
Yields: the Discount Yield • Weaknesses • Use of 360 days • Return based on par value and not price
Alternative Calculation: Simple Interest • Yd = Par value - Price x _ 365______ Price Number of days to maturity • $10,000 - $9,791 x _365_ = $9,791 180 4.33%
Alternative Calculation: Compound Interest • Price(1 + i)t = Face Value • Example • price: $9,791face value: $10,000time period: 180 days$9,791(1 + i)0.49315 = $10,000i = (1.02135)2.0278 - 1 = 4.38%