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In this problem, we are given a diagram and need to prove the congruence of certain angles using the concept of supplementary angles. We use the properties of vertical angles and solve for the unknown angle measure.
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Warm Up Given: Diagram as shown Prove: <1 congruent <3 Hint: Think of Supplementary Angles! • <ABC is a straight < 1. Assumed • <1 is supp to < 2 2. If 2 adjacent <s form • a straight <, they are supp 3. <DBE is a straight < 3. Same as 1 4. <2 is supp to <3 4. Same as 2 5. <1 congruent to <3 5. Supplements of the same < are congruent
2.8 Vertical Angles http://www.phschool.com/atschool/academy123/html/bbapplet_wl-problem-431584.html
Opposite Rays: Two collinear rays that have a common endpoint and extend in different directions B A C Ray AB and ray AC are opposite rays.
B A C D Ray BA and Ray CD are not opposite rays. X Y V U Ray UV and Ray XY are not opposite rays. NO common end point.
Vertical Angles: when ever two lines intersect, two pairs of vertical angles are formed. You can assume Vertical Angles!
Def: Two angles are vertical angles if the rays forming the sides of one angle and the rays forming the sides of the other are opposite rays. 3 E B A 2 1 4 C D <1 &<2; <3 & <4 are vertical angles.
T18: Vertical angles are congruent. 6 7 5 Given: diagram Prove <5 congruent to <7 Hint: use supplementary angles
2.4 problem Therefore <5 <7
Given: <2 congruent to <3 Prove: <1 congruent to <3 1 2 3
5 4 6 m<4 = 2x +5 m<5 = x + 30 Find the m<4 and m<6
Vertical angles are congruent so just set them equal to each other and solve for x. REMEMBER to plug x back in to find the angle. The measure of <6 = 180-55 = 125