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This document covers essential concepts involving the perimeter of triangles and angle relationships in circles. Firstly, it calculates the perimeter of a triangle with given side lengths of AM = 8, BP = 7, and CA = 18. Next, it delves into various cases of angle relationships based on the vertex position—on the circle, inside it, or outside. Each case includes multiple practice examples with solutions for finding the measures of angles formed by intersecting lines and arcs. This comprehensive guide serves as a practical resource for mastering geometry concepts.
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Warm-up A 1. Let AM = 8, BP = 7, and CA = 18. Find the perimeter of the triangle. N M 50 C P 3. MCY = 270 Find BC. B 2. Find ACB 20 B A M 312 20 90 B 24 C C Y
6.5 Other Angle Relationships – On, Inside, and Outside of the Circle
Case I:Vertex is ON the circle ANGLE ARC ARC ANGLE
REMEMBER: Find m1. A B 1 124° C m1 = 62º
Ex. 1: Find m1. 1 78° m1 = 39º
108° Ex. 2: Find m1. 1 m1 = 126º
Case II:Vertex is inside the circle A ARC B ANGLE D ARC C Looks like a PLUS sign!
Ex. 4 Find m1. 93° A B 1 D C 113° m1 = 103º
Ex. 5 Find mQT. mQT = 100º N Q 84º 92º M T
Case III:Vertex is outside the circle C ANGLE small ARC A D LARGE ARC B LARGE ARC LARGE ARC small ARC ANGLE small ARC ANGLE
Ex. 6 Find m1. 1 15° A D 65° B m1 = 25º
Ex. 7 Find mAB. mAB = 16º A 27° 70° B
Ex. 8 Find m1. 260° 1 m1 = 80º
52.5º 4 32º 2 Brain Buster 3 105º 36.5º 1 105º 16º