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Warm Up

Preview. Warm Up. California Standards. Lesson Presentation. 18. – 3. Warm Up Add or subtract. 1. –6 + (–5) 2. 4 – (–3) 3. –2 + 11 Multiply or divide. 4. –5(–4) 5. 6. 7(–8). –11. 7. 9. 20. – 6. – 56. California Standards.

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Warm Up

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  1. Preview Warm Up California Standards Lesson Presentation

  2. 18 –3 Warm Up Add or subtract. 1. –6 + (–5) 2. 4 – (–3) 3. –2 + 11 Multiply or divide. 4. –5(–4) 5. 6. 7(–8) –11 7 9 20 –6 –56

  3. California Standards AF4.1 Solve two-step linear equations and inequalities in one variable over the rational numbers, interpret the solution or solutions in the context from which they arose, and verify the reasonableness of the results. Also covered: AF1.1

  4. Two-step equations contain two operations. For example, the equation 6x 2 = 10 contains multiplication and subtraction. 6x 2 = 10 Multiplication Subtraction

  5. x 2 - 17 = 21 Additional Example 1A: Translating Sentences into Two-Step Equations Translate the sentence into an equation. 17 less than the quotient of a number x and 2 is 21. 17 less than the quotientof a number x and 2 is 21. (x ÷ 2) – 17 = 21

  6. Additional Example 1B: Translating Sentences into Two-Step Equations Translate the sentence into an equation. Twice a number m increased by –4 is 0. Twice a number mincreased by –4 is 0. 2 ● m+ (–4) = 0 2m + (–4) = 0

  7. Check It Out! Example 1A Translate the sentence into an equation. 7 more than the product of 3 and a number t is 21. 7more thanthe product of 3 and a number tis 16. 3 ● t+ 7 = 16 3t + 7 = 16

  8. x 4 - 3 = 7 Check It Out! Example 1B Translate the sentence into an equation. 3 less than the quotient of a number x and 4 is 7. 3 less than the quotientof a number x and 4 is 7. (x ÷ 4)– 3 = 7

  9. Additional Example 2A: Solving Two-Step Equations Using Division Solve 3x + 4 = –11. Note that x is multiplied by 3. Then 4 is added. Work backward: Since 4 is added to 3x, subtract 4 from both sides. Step 1: 3x + 4 = –11 – 4 – 4 3x = –15 3x = –15 Since x is multiplied by 3, divide both sides by 3 to undo the multiplication. Step 2: 3 3 x = –5

  10. Additional Example 2B: Solving Two-Step Equations Using Division Solve 8 = –5y – 2. Since 2 is subtracted from –5y, add 2 to both sides to undo the subtraction. 8 = –5y – 2 + 2 + 2 10= –5y 10= –5y Since y is multiplied by –5, divide both sides by –5 to undo the multiplication. –5 –5 –2= y or y = –2

  11. Check It Out! Example 2A Solve 7x + 1 = –13. Note that x is multiplied by 7. Then 1 is added. Work backward: Since 1 is added to 7x, subtract 1 from both sides. Step 1: 7x + 1 = –13 – 1 – 1 7x = –14 7x = –14 Since x is multiplied by 7, divide both sides by 7 to undo the multiplication. Step 2: 7 7 x = –2

  12. Check It Out! Example 2B Solve 12 = –5y – 3. 12 = –5y – 3 Since 3 is subtracted from –5y, add 3 to both sides to undo the subtraction. + 3 + 3 15= –5y Since y is multiplied by –5, divide both sides by –5 to undo the multiplication. 15= –5y –5 –5 –3= y or y = –3

  13. m7 Note that m is divided by 7. Then 4 is added. Work backward: Since 4 is added to , subtract 4 from both sides. 4 + = 9 m7 m7 = 5 m7 (7)= 5(7) Additional Example 3A: Solving Two-Step Equations Using Multiplication m 7 Solve 4 + = 9. Step 1: – 4 – 4 Since m is divided by 7, multiply both sides by 7 to undo the division. Step 2: m = 35

  14. z 12 Since 3 is subtracted from t , add 3 to both sides to undo the subtraction. 14 = – 3 z2 z 2 17 = z 2 (2)17 = (2) Additional Example 3B: Solving Two-Step Equations Using Multiplication z 2 Solve 14 = – 3. Step 1: + 3 + 3 z is divided by 2, multiply both sides by 2 to undo the division. Step 2: 34= z

  15. k 6 Note that k is divided by 6. Then 2 is added. Work backward. Since 2 is added to , subtract 2 from both sides. 2 + = 9 k 6 k 6 = 7 k 6 (6)= 7(6) Check It Out! Example 3A k 6 Solve 2 + = 9. Step 1: – 2 – 2 Since k is divided by 6, multiply both sides by 6 to undo the division. Step 2: k = 42

  16. p 14 Since 2 is subtracted from t , add 2 to both sides to undo the subtraction. 10 = – 2 p4 p 4 12 = p 4 (4)12 = (4) Check It Out! Example 3B p 4 Solve 10 = – 2. Step 1: + 2 + 2 p is divided by 4, multiply both sides by 4 to undo the division. Step 2: 48= p

  17. cost of DVD player cost of DVDs + = total cost $120 + 14d = $204 Additional Example 4: Consumer Math Application Donna buys a portable DVD player that costs $120. She also buys several DVDs that cost $14 each. She spends a total of $204. How many DVDs does she buy? Let d represent the number of DVDs that Donna buys. That means Donna can spend $14d plus the cost of the DVD player.

  18. –120 –120 14d = 84 $120 + 14d = $204 14 14 Additional Example 4 Continued Donna buys a portable DVD player that costs $120. She also buys several DVDs that cost $14 each. She spends a total of $204. How many DVDs does she buy? 120 + 14d = 204 14d = 84 d = 6 Donna purchased 6 DVDs.

  19. cost of MP3 player cost of songs + = total cost $249 + 0.99s = $277.71 Check It Out! Example 4 John buys an MP3 player that costs $249. He also buys several songs that cost $0.99 each. He spends a total of $277.71. How many songs does he buy? Let s represent the number of songs that John buys. That means John can spend $0.99s plus the cost of the MP3 player.

  20. –249 –249 0.99s = 28.71 $249 + 0.99s = $277.71 0.99 0.99 Check It Out! Example 4 Continued John buys an MP3 player that costs $249. He also buys several songs that cost $0.99 each. He spends a total of $277.71. How many songs does he buy? 249 + 0.99s = 277.71 0.99s = 28.71 s = 29 John purchased 29 songs.

  21. w x 2 4 Lesson Quiz Translate the sentence into an equation. 1.The product of –3 and a number c, plus 14, is –7. Solve. 2. 17 = 2x – 3 3. –4m + 3 = 15 4. –5 = 1 5. 2 = 3 – –3c + 14 = –7 10 –3 4 12 6.A discount movie pass costs $14. With the pass, movie tickets cost $6 each. Fern spent a total of $68 on the pass and movie tickets. How many movies did he see? 9

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